What is the power when resistance is 22 ohms and applied voltage is 58 volts? Round to one decimal place.

What is the power when resistance is 22 ohms and applied voltage is 58 volts? Round to one decimal place.

• A. 150.0 W
• B. 152.9 W
• C. 156.4 W
• D. 160.0 W

Answer: (B)

In a DC circuit, the power dissipated by a resistor can be found with P = V^2 / R. With V = 58 volts and R = 22 ohms, compute 58^2 = 3364, then 3364 / 22 = 152.909..., which rounds to 152.9 watts. You can also check this by finding the current I = V / R = 58 / 22 ≈ 2.636 A, and then P = VI ≈ 58 × 2.636 ≈ 152.9 W, or by P = I^2R = (2.636)^2 × 22 ≈ 152.9 W. The result is about 152.9 W.

In a DC circuit, the power dissipated by a resistor can be found with P = V^2 / R. With V = 58 volts and R = 22 ohms, compute 58^2 = 3364, then 3364 / 22 = 152.909..., which rounds to 152.9 watts. You can also check this by finding the current I = V / R = 58 / 22 ≈ 2.636 A, and then P = VI ≈ 58 × 2.636 ≈ 152.9 W, or by P = I^2R = (2.636)^2 × 22 ≈ 152.9 W. The result is about 152.9 W.